# Line slope calculator 7x+6y=48

**Straight line given by points A[0; 8] and B[6; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.1667x+8

**Canonical form of the line equation:**7x+6y-48 = 0

**Parametric form of the line equation:**

x = 6t

y = -7t+8 ; t ∈ R

**Slope:**m = -1.1667

**Slope angle of line: φ =**-49°23'55″ = -0.8622 rad

**X intercept:**x

_{0}= 6.8571

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 5.2063

**The length of the segment AB: |AB| =**9.2195

**Vector: AB =**(6; -7)

**Normal vector: n =**(7; 6)

**Midpoint of the segment AB: M =**[3; 4.5]

**Perpendicular Bisector equation:**6x-7y+13.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (6; 1) ; |OB| = 6.0828**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 80°32'16″ = 1.4056 rad**